Sign Up

Sign Up to our social questions and Answers Engine to ask questions, answer people’s questions, and connect with other people.

Have an account? Sign In

Have an account? Sign In Now

Sign In

Login to our social questions & Answers Engine to ask questions answer people’s questions & connect with other people.

Sign Up Here

Forgot Password?

Don't have account, Sign Up Here

Forgot Password

Lost your password? Please enter your email address. You will receive a link and will create a new password via email.

Have an account? Sign In Now

You must login to ask a question.

Forgot Password?

Need An Account, Sign Up Here

Please briefly explain why you feel this question should be reported.

Please briefly explain why you feel this answer should be reported.

Please briefly explain why you feel this user should be reported.

Sign InSign Up

The Archive Base

The Archive Base Logo The Archive Base Logo

The Archive Base Navigation

  • SEARCH
  • Home
  • About Us
  • Blog
  • Contact Us
Search
Ask A Question

Mobile menu

Close
Ask a Question
  • Home
  • Add group
  • Groups page
  • Feed
  • User Profile
  • Communities
  • Questions
    • New Questions
    • Trending Questions
    • Must read Questions
    • Hot Questions
  • Polls
  • Tags
  • Badges
  • Buy Points
  • Users
  • Help
  • Buy Theme
  • SEARCH
Home/ Questions/Q 4242740
In Process

The Archive Base Latest Questions

Editorial Team
  • 0
Editorial Team
Asked: May 21, 20262026-05-21T03:29:00+00:00 2026-05-21T03:29:00+00:00

I’m running the following code: class Foo { private $var = 0; function isVarSet

  • 0

I’m running the following code:

class Foo {  
    private $var = 0;

    function isVarSet () {
           return ($this->var != 0);
    }
}

...

foo = new Foo();

results in an “undefined property” notice: foo::$var on my PHP (ver. 5.3.5).

if I rewrite just the function isVarSet():

function isVarSet() {
    if (isset($this->var))
        return ($this->var != 0);
    return false;
}

the notice disappears.

This I do not understand. $var is set in both cases, why would it be an undefined property? Why do I need to use isset() to prevent this notice? Also, why does the notice refer to $var with the scope operator :: ? I’m not using a static class, I’m using an instance foo. $foo->isVarSet() should access a $var that is both defined and non-static.

I’ve been working on this for hours now and read all other answers on the undefined property notice, but this one I just don’t get. Please enlighten me, StackOverFlow masters.


the code in my application:

<?php

class session {

    private $userId = 0;

    function __construct() {
    session_start();
    $this->setUserId();
    }

    public function isLoggedIn() {
    //if (isset($this->userId))
        return ($this->userId != 0);
    //return false;
    }

    function getUserId() {
    if (isset($this->userId))
        return $this->userId;
    else
        return false;
    }

    private function setUserId() {
    if (isset($_SESSION['userId'])) {
        $this->userId = $_SESSION['userId'];        
    } else 
        unset($this->userId);       
    }

    public function login($user) {
    if ($user != null) {        
        $_SESSION['userId'] = $user->id;
        $this->userId = $user->id;
    }
    }

     public function logout() {
    unset($_SESSION['userId']);
    unset($this->userId);   
    }    
}

$session = new Session();

?>

The call to the session class is made like so:

if ($session->isLoggedIn())
redirectToLocation("../public/index.php");
  • 1 1 Answer
  • 0 Views
  • 0 Followers
  • 0
Share
  • Facebook
  • Report

Leave an answer
Cancel reply

You must login to add an answer.

Forgot Password?

Need An Account, Sign Up Here

1 Answer

  • Voted
  • Oldest
  • Recent
  • Random
  1. Editorial Team
    Editorial Team
    2026-05-21T03:29:01+00:00Added an answer on May 21, 2026 at 3:29 am

    (after the whole edit).

    What do you think this line does (in setUserId):

     unset($this->userId);
    

    You might just want to set it to 0 as previous (which you recognize as not logged in:

     $this->userId = 0;
    

    Or:

     $this->userId = null;
    

    Take your pick.

    • 0
    • Reply
    • Share
      Share
      • Share on Facebook
      • Share on Twitter
      • Share on LinkedIn
      • Share on WhatsApp
      • Report

Sidebar

Related Questions

I'm parsing an RSS feed that has an &#8217; in it. SimpleXML turns this
I have this code: - (void)parser:(NSXMLParser *)parser foundCDATA:(NSData *)CDATABlock { NSString *someString = [[NSString
I am currently running into a problem where an element is coming back from
I have a French site that I want to parse, but am running into
I want use html5's new tag to play a wav file (currently only supported
link Im having trouble converting the html entites into html characters, (&# 8217;) i
Does anyone know how can I replace this 2 symbol below from the string
this is what i have right now Drawing an RSS feed into the php,
I have some data like this: 1 2 3 4 5 9 2 6
Seemingly simple, but I cannot find anything relevant on the web. What is the

Explore

  • Home
  • Add group
  • Groups page
  • Communities
  • Questions
    • New Questions
    • Trending Questions
    • Must read Questions
    • Hot Questions
  • Polls
  • Tags
  • Badges
  • Users
  • Help
  • SEARCH

Footer

© 2021 The Archive Base. All Rights Reserved
With Love by The Archive Base

Insert/edit link

Enter the destination URL

Or link to existing content

    No search term specified. Showing recent items. Search or use up and down arrow keys to select an item.