Sign Up

Sign Up to our social questions and Answers Engine to ask questions, answer people’s questions, and connect with other people.

Have an account? Sign In

Have an account? Sign In Now

Sign In

Login to our social questions & Answers Engine to ask questions answer people’s questions & connect with other people.

Sign Up Here

Forgot Password?

Don't have account, Sign Up Here

Forgot Password

Lost your password? Please enter your email address. You will receive a link and will create a new password via email.

Have an account? Sign In Now

You must login to ask a question.

Forgot Password?

Need An Account, Sign Up Here

Please briefly explain why you feel this question should be reported.

Please briefly explain why you feel this answer should be reported.

Please briefly explain why you feel this user should be reported.

Sign InSign Up

The Archive Base

The Archive Base Logo The Archive Base Logo

The Archive Base Navigation

  • SEARCH
  • Home
  • About Us
  • Blog
  • Contact Us
Search
Ask A Question

Mobile menu

Close
Ask a Question
  • Home
  • Add group
  • Groups page
  • Feed
  • User Profile
  • Communities
  • Questions
    • New Questions
    • Trending Questions
    • Must read Questions
    • Hot Questions
  • Polls
  • Tags
  • Badges
  • Buy Points
  • Users
  • Help
  • Buy Theme
  • SEARCH
Home/ Questions/Q 712461
In Process

The Archive Base Latest Questions

Editorial Team
  • 0
Editorial Team
Asked: May 14, 20262026-05-14T04:51:03+00:00 2026-05-14T04:51:03+00:00

I’m running the following code on a list of strings to return a list

  • 0

I’m running the following code on a list of strings to return a list of its words:

words = [re.split('\\s+', line) for line in lines]

However, I end up getting something like:

[['import', 're', ''], ['', ''], ['def', 'word_count(filename):', ''], ...]

As opposed to the desired:

['import', 're', '', '', '', 'def', 'word_count(filename):', '', ...]

How can I unpack the lists re.split('\\s+', line) produces in the above list comprehension? Naïvely, I tried using * but that doesn’t work.

(I’m looking for a simple and Pythonic way of doing; I was tempted to write a function but I’m sure the language accommodates for this issue.)

  • 1 1 Answer
  • 0 Views
  • 0 Followers
  • 0
Share
  • Facebook
  • Report

Leave an answer
Cancel reply

You must login to add an answer.

Forgot Password?

Need An Account, Sign Up Here

1 Answer

  • Voted
  • Oldest
  • Recent
  • Random
  1. Editorial Team
    Editorial Team
    2026-05-14T04:51:03+00:00Added an answer on May 14, 2026 at 4:51 am
    >>> import re
    >>> from itertools import chain
    >>> lines = ["hello world", "second line", "third line"]
    >>> words = chain(*[re.split(r'\s+', line) for line in lines])
    

    This will give you an iterator that can be used for looping through all words:

    >>> for word in words:
    ...    print(word)
    ... 
    hello
    world
    second
    line
    third
    line
    

    Creating a list instead of an iterator is just a matter of wrapping the iterator in a list call:

    >>> words = list(chain(*[re.split(r'\s+', line) for line in lines]))
    
    • 0
    • Reply
    • Share
      Share
      • Share on Facebook
      • Share on Twitter
      • Share on LinkedIn
      • Share on WhatsApp
      • Report

Sidebar

Related Questions

I ran into a problem. Wrote the following code snippet: teksti = teksti.Trim() teksti
link Im having trouble converting the html entites into html characters, (&# 8217;) i
I have a string like this: La Torre Eiffel paragonata all’Everest What PHP function
I have a French site that I want to parse, but am running into
I have this code to decode numeric html entities to the UTF8 equivalent character.
I'm using v2.0 of ClassTextile.php, with the following call: $testimonial_text = $textile->TextileRestricted($_POST['testimonial']); ... and
I would like to run a str_replace or preg_replace which looks for certain words
I'm parsing an RSS feed that has an ’ in it. SimpleXML turns this
I have this code: - (void)parser:(NSXMLParser *)parser foundCDATA:(NSData *)CDATABlock { NSString *someString = [[NSString
I am currently running into a problem where an element is coming back from

Explore

  • Home
  • Add group
  • Groups page
  • Communities
  • Questions
    • New Questions
    • Trending Questions
    • Must read Questions
    • Hot Questions
  • Polls
  • Tags
  • Badges
  • Users
  • Help
  • SEARCH

Footer

© 2021 The Archive Base. All Rights Reserved
With Love by The Archive Base

Insert/edit link

Enter the destination URL

Or link to existing content

    No search term specified. Showing recent items. Search or use up and down arrow keys to select an item.