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Home/ Questions/Q 743397
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Editorial Team
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Editorial Team
Asked: May 14, 20262026-05-14T08:51:32+00:00 2026-05-14T08:51:32+00:00

I’m searching for a string in a website and checking to see if the

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I’m searching for a string in a website and checking to see if the location of this string is in the expected location. I know the string starts at the 182nd character, and if I print temp it will even tell me that it is 182, however, the if statement says 182 is not 182.

Some code

f = urllib.urlopen(link)

 #store page contents in 's'
 s = f.read()
 f.close()
 temp = s.find('lettersandnumbers')

 if (htmlsize == "197"):
  #if ((s.find('lettersandnumbers')) == "182"):
  if (temp=="182"):
   print "Glorious"
   doStuff()
  else:
   print "HTML not correct.  Aborting."
 else:
  print htmlsize
  print "File size is incorrect.  Aborting."
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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-14T08:51:32+00:00Added an answer on May 14, 2026 at 8:51 am

    Im not a python guru, but ill take a shot

    Try it like this

    if (temp == 182)
    

    Why? See SilentGhost answer. It involves types

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