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Home/ Questions/Q 9061669
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Editorial Team
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Editorial Team
Asked: June 16, 20262026-06-16T15:32:39+00:00 2026-06-16T15:32:39+00:00

I’m seeking for a proper structure for a big array which will be frequently

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I’m seeking for a proper structure for a big array which will be frequently updated. Thanks for your help!
Here’s the background:
I want to draw a continuous curve to represent a sound wave in a certain time period. For the accuracy, the array length will be nearly 44100(the CD format).And I just want to represent the last second wave, so the array will be updated very frequently – for every 1/44100 sec, the first element will be eliminated and a new last element will be inserted to the array.

For avoiding the frequent “malloc/realloc/new”, what my current solution is using an Circular Queue which has a fixed size as 44100, but somehow I don’t feel this is most proper solution, if I want to dynamically resize the queue, it will be a heavy cost.
This kind of situation should be quite often, I think there maybe some good patent for this issue.
Thanks guys!

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  1. Editorial Team
    Editorial Team
    2026-06-16T15:32:40+00:00Added an answer on June 16, 2026 at 3:32 pm

    I assume you’re always having a fixed number of items in the array. As such I’d just use a ring buffer in any case (not sure whether that’s what you refer to as a “Circular Queue”, but I assume you’d use a dynamic length? If so, why? Is there no specific absolute (and practical) maximum?), i.e. a static array with a variable entry point as its start:

    const unsigned int buffer_length = 500000;
    float *buffer = new float[buffer_length];
    
    unsigned int buffer_write = 0;
    
    // append a value...
    buffer[buffer_write] = my_value;
    // ...and move the write/end position:
    buffer_write = (buffer_write + 1) % buffer_length;
    

    To output/use the values, you can use the following formula for index of the first entry to read:

    unsigned int start_position = (buffer_length + buffer_write - length_to_read) % buffer_length;
    

    To iterate, you just add position after position, again using modulo to jump back to the beginning of the array.

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