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Home/ Questions/Q 8269843
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Editorial Team
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Editorial Team
Asked: June 8, 20262026-06-08T06:21:54+00:00 2026-06-08T06:21:54+00:00

I’m sendint serialized data to items.php file with AJAX, I’m checking result with FireBug,

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I’m sendint serialized data to items.php file with AJAX, I’m checking result with FireBug, AJAX send data like this category=2 my items.php file is:

<?php
require_once('db.php');
if (isset ($_POST['category'])) {
$kat = mysql_real_escape_string($_POST['category']);
if ($kat == 0){
 $kat = '';
}elseif ($kat == 1){
 $kat = 'ORDER BY date DESC';
}elseif ($kat == 2) {
    $kat = 'ORDER BY price DESC';
}elseif ($kat == 3) {
    $kat = 'ORDER BY price';
}
}else{ $kat = '';}
        $query = "SELECT * FROM prekes ".$kat."";
        mysql_query("SET NAMES 'UTF8'");
        $q = mysql_query($query) or die(mysql_error());
        $i = 0;
        while($f = mysql_fetch_array($q)){

        echo '<div kaina="'.$f['kaina'].'" class="prekes"><img src="prekes/'.$f['foto'].'">'.$f['pavadinimas'].'<br /><strong>'.$f['kaina'].'Lt </strong></div>';
        }
        ?>

and here is my AJAX success function:

   $.ajax({
        type: 'POST',
        url: 'items.php',
        data: cleaned,
        success: function () {          
                              $('#items').fadeOut("fast").load("items.php?ts="+ $.now()).fadeIn("fast");
    }
   }); 

Div refreshes after success, but I’m getting old, unordered result. Why does it happening?

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-06-08T06:21:56+00:00Added an answer on June 8, 2026 at 6:21 am

    Since load method uses jQuery get method internally, I guess you are getting cached data. Make sure to send a unique key as part of the querystring and it will give you the new content /result /uncached data. You may use the Date object to get create a new unique string;

    $('#items').fadeOut("fast").load("items.php?ts="+new Date().getTime())
    

    EDIT : jQuery has a small method called $.now() to give you a unique timestamp. you may use that instead of writing the Date().getTime() method.

    $('#items').fadeOut("fast").load("items.php?ts="+ $.now())
    

    The $.now() method is a shorthand for the number returned by the
    expression (new Date).getTime().

    Thanks Kevin for pointing out. 🙂

    EDIT 2 : After seeing the code

    1) You are not passing the category querystring value which is being used to return the ordered list.You should pass that like this

    $('#items').fadeOut("fast").load("items.php?category=2&ts="+ $.now())
    

    2) load method is a GET request. in your PHP code(items.php) you are accessing it using $_POST(is that correct ? Shouldnt be $_GET ?

    So Change

    $kat = mysql_real_escape_string($_POST['category']);
    

    to

    $kat = mysql_real_escape_string($_GET['category']);
    
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