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Home/ Questions/Q 3242694
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Editorial Team
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Editorial Team
Asked: May 17, 20262026-05-17T18:20:43+00:00 2026-05-17T18:20:43+00:00

I’m setting up a Twitter-style trending topics box for my forum. I’ve got the

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I’m setting up a Twitter-style “trending topics” box for my forum. I’ve got the most popular /words/, but can’t even begin to think how I will get popular phrases, like Twitter does.

As it stands I just get all the content of the last 200 posts into a string and split them into words, then sort by which words are used the most. How can I turn this from most popular words into the most popular phrases?

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  1. Editorial Team
    Editorial Team
    2026-05-17T18:20:44+00:00Added an answer on May 17, 2026 at 6:20 pm

    One technique you might consider is the use of ZSETs in Redis for something like this. If you’ve got very large sets of data, you’ll find that you can do something like this:

    $words = explode(" ", $input); // Pseudo-code for breaking a block of data into individual words.
    $word_count = count($words);
    
    $r = new Redis(); // Owlient's PHPRedis PECL extension
    $r->connect("127.0.0.1", 6379);
    
    function process_phrase($phrase) {
        global $r;
        $phrase = implode(" ", $phrase);
        $r->zIncrBy("trending_phrases", 1, $phrase);
    }
    
    for($i=0;$i<$word_count;$i++)
        for($j=1;$j<$word_count - $i;$j++)
            process_phrase(array_slice($words, $i, $j));
    

    To retrieve the top phrases, you’d use this:

    // Assume $r is instantiated like it is above
    $trending_phrases = $r->zReverseRange("trending_phrases", 0, 10);
    

    $trending_phrases will be an array of the top ten trending phrases. To do things like recent trending phrases (as opposed to a persistent, global set of phrases), duplicate all of the Redis interactions above. For each interaction, use a key that’s indicative of, say, today’s timestamp and tomorrow’s timestamp (i.e.: days since Jan 1, 1970). When retrieving the results with $trending_phrases, just retrieve both today and tomorrow’s (or yesterday’s) key and use array_merge and array_unique to find the union.

    Hope this helps!

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