Question

I’m somewhat in difficulty. (I’m pro in regexps but not much used them in scala/java).
I have numeric string of 11 chars in length, need just last 10, so:

val Pattern = """(\d{10})$""".r
"79283767219" match {
  case Pattern(m) => m
}

It gives MatchError, but why?! What have I misunderstood?

Answer 1

Because you have 11 digits, not 10. You can set “10 and more” with {10,}. To match only end of the string you need to explicitly specify full pattern:

 val Pattern = """.*(\d{10})$""".r

Update: until you’re on Scala 2.10 and you can use Daniel’s unanchored you can workaround it like so:

Pattern.findFirstIn("79283767219")