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Home/ Questions/Q 6813881
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Editorial Team
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Editorial Team
Asked: May 26, 20262026-05-26T20:37:19+00:00 2026-05-26T20:37:19+00:00

I’m somewhat of a noob to python but I’m trying to create a recursive

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I’m somewhat of a noob to python but I’m trying to create a recursive function which works just like the built in range function:

def Range (lo, hi):
    if lo >= hi:
        return []
    else:
        return [lo, Range (lo+1,hi)]

but its returning multiple lists.

Instead of [3,4,5,6], which is what I want, its returning [3,[4,[5,[6,[]]]]]
Why is this and how do I fix it?

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  1. Editorial Team
    Editorial Team
    2026-05-26T20:37:19+00:00Added an answer on May 26, 2026 at 8:37 pm

    When you recurse like that, Range returns a list each time:

    Range(3,7)
    # translates to
    [3, Range(4,7)]
    # which translates to
    [3, [4, Range(5,7)]]
    # etc.
    

    In order to avoid this, add your lists together:

    def Range (lo, hi):
        if lo >= hi:
            return []
        else:
            return [lo] + Range(lo+1, hi)
    

    EDIT:

    As @delnan points out, this function is very inefficient – it both recurses in a language without tail-call optimization* and it generates two (possibly three) new lists for each level of recursion. @mipadi’s answer is more performant because it creates only one list (the acc or accumulator argument) and passes it as it recurses.

    * This may not be true for the Python language, but I’m 99% sure it is true for the most common implementation of Python, namely CPython.

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