Question

I’m sorry if this is too entry-level, but I tried implementing the library function of strcpystrncat() as follows:

#include <stdio.h>

void strncat (char *s, char *t, int n) {
// malloc to extend size of s
s = (char*)malloc (strlen(t) + 1);

// add t to the end of s for at most n characters
while (*s != '\0') // move pointer
    s++;

int count = 0;

while (++count <= n)
    *s++ = *t++;

*(++s) = '\0';
}

int main () {
char *t = " Bluish";
char *s = "Red and";

// before concat
printf ("Before concat: %s\n", s);

strncat(s, t, 4);

// after concat
printf ("After concat: %s\n", s);

return 0;
}

It compiles and runs fine…just that it doesn’t concatenate at all!

Greatly appreciate any feedback…thanks!

Answer 1

It seems like you redefine s pointer with your malloc, since you’ve done it, it doesn’t points to your first concatenated string.

First of all function return type should be char*

char* strncat (char *s, char *t, int n)

After, I think you should create local char pointer.

char* localString;

use malloc for allocate space with this pointer

localString = malloc (n + strlen(s) + 1); 

and you don’t need to make type cast here, cuz malloc do it itself

in fact, you should use your size parameter (n) here, not strlen(t)

and after doing all concatenation operation with this pointer return it

return localString