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Home/ Questions/Q 7040351
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Editorial Team
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Editorial Team
Asked: May 28, 20262026-05-28T01:54:29+00:00 2026-05-28T01:54:29+00:00

I’m starting with this query: SELECT TOP 1 Parties.FirstName + ‘ ‘ + Parties.MiddleName

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I’m starting with this query:

SELECT     TOP 1 Parties.FirstName + ' ' + Parties.MiddleName + ' ' + Parties.LastName AS     Plaintiffs
FROM         Jackets INNER JOIN
                  JacketPartyLinks ON Jackets.Id =     JacketPartyLinks.Jacket_JacketPartyLink INNER JOIN
                      Parties ON Parties.Id = JacketPartyLinks.JacketPartyLink_Party
WHERE     (Jackets.Id = @JacketID) AND (JacketPartyLinks.Role = 0)

What I’d like to accomplish is to take a count of what’s returned, and if it’s one row, do nothing. If it’s more than one row, add something like “, et al”. Notice that this query returns a single column, and it while it should be able to run standalone, it also needs to work as a subquery.

How can this be done?

EDIT: Add TOP 1

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-28T01:54:29+00:00Added an answer on May 28, 2026 at 1:54 am

    Use top and count..over and then wrap it in an outer query, like so:

    select
        Plantiffs + case when PlantiffCount > 1 then ', et al' else '' end as Plantiffs
    from
        (
            SELECT TOP 1
                Parties.FirstName + ' ' + Parties.MiddleName + ' ' + Parties.LastName as Plantiffs,
                count(1) over () as PlantiffCount
            FROM
                Jackets 
                INNER JOIN JacketPartyLinks ON 
                    Jackets.Id = JacketPartyLinks.Jacket_JacketPartyLink 
                INNER JOIN Parties ON 
                    Parties.Id = JacketPartyLinks.JacketPartyLink_Party
            WHERE
                (Jackets.Id = @JacketID) AND (JacketPartyLinks.Role = 0)
            order by Parties.LastName asc
        ) x
    

    The over () part after count tells it to count all rows and not group by anything. This is why there isn’t a group by clause in that query. You can use over with any aggregate function, which is pretty nifty.

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