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Home/ Questions/Q 8955269
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Editorial Team
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Editorial Team
Asked: June 15, 20262026-06-15T14:30:47+00:00 2026-06-15T14:30:47+00:00

I’m struggling to understand Java Simple . Something about it looks very cool but

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I’m struggling to understand Java Simple. Something about it looks very cool but I can’t get my head around how to use it.

I can’t find a ‘Hello World’ example that demonstrates how the bits-and-pieces fit together. I’m looking for something like this;

Expected output

<durr/>

Demo.java

public class Demo {
    public static void main(String[] args) {
       String str = new Foo();
       System.out.println(str);
    }
}

Foo.java

import org.simpleframework.xml.Root;

@Root
public class Foo{
    // Something
}

Compile and run

javac Demo.java Foo.java
java Demo

Summary

What is the simplest demo that can output <durr/> using Simple?

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-06-15T14:30:49+00:00Added an answer on June 15, 2026 at 2:30 pm

    Quoting directly from simple’s documentation:

    To serialize an instance of the above object a Persister is required. The persister object is then given an instance of the annotated object and an output result, which is a file in this example. Other output formats are possible with the persister object.

    So basically, I would say your Demo class could be written in the following way:

    import java.io.File;
    import org.simpleframework.xml.Serializer; 
    import org.simpleframework.xml.core.Persister;
    
    public static void main(String[] args) throws Exception {
    
       Foo foo = new Foo();
       Serializer serializer = new Persister(); 
       File result = new File("example.xml"); // XML OUTPUT WILL BE WRITTEN HERE
       serializer.write(foo, result);
    }
    

    Once again, based on the documentation I would say this will generate a <foo/> tag , because it’s your class’ name, to change it to <duur/> output you have to redefine the name in the root tag in your Foo class, like this:

    import org.simpleframework.xml.Root;
    
    @Root(name="durr")
    public class Foo{
     // Something
    }
    
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