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Home/ Questions/Q 3853910
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Editorial Team
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Editorial Team
Asked: May 19, 20262026-05-19T17:32:32+00:00 2026-05-19T17:32:32+00:00

I’m struggling with this for several days now. I want to create a functions

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I’m struggling with this for several days now.

I want to create a functions that goes through a directory, pick all the files with an extension *.csv and read the data in them.

I created a function that is supposed to check each file name that is legal, by checking that the string ends with .csv. To do this, I want to go to the end of the char * array. I tried this:

 char * point = file_name;
 while (point != "\0"){
    point += 1;
 }

which goes through the char * array without finding and “\0”.

If I write

*point != "\0"

The compiler warns me that I’m comparing and int to a char.

I should note that I get the filename using

 dirent->d_name
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  1. Editorial Team
    Editorial Team
    2026-05-19T17:32:32+00:00Added an answer on May 19, 2026 at 5:32 pm

    point != "\0" compares a pointer to another pointer, which is not what you want.

    You want to compare whatever point points to , to a char with the value 0. So use e.g.

    *point != '\0'; 
    

    Note, if you want to find the end of the string, you could also do

    point = file_name + strlen(filename); 
    

    If you want to check whether a string ends in .csv, you could also do something like

    if((point = strrchr(filename,'.')) != NULL ) {
         if(strcmp(point,".csv") == 0) {
              //ends with csv
          }
      }
    

    EDIT : fixed formatting

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