Question

I’m stuck on an mysql query. I usually just put the result set into an array and use var = $row['column']; . I am unable to do that this time. The query is as such.

$dbTaskRecords = mysql_query("Select Time, TruckId, TaskNo, PickupLocation, DropOffLocation
From booking 
Where driver='$driver' 
    And Date= CAST('$Date_search' AS DATE) 
Union All
Select Time, TruckId, TaskNo, PickupLocation, DropOffLocation
From returnbooking
WHERE driver='$driver' 
    And Date= CAST('$Date_search' AS DATE) 
Order By TaskNo Asc");

If I try to use:
$row = mysql_fetch_array($dbTaskRecords);

I get an error.

How do I go about getting the outputs to variables?

Thanks guys.

Answer 1

mysql_fetch_array() expects parameter 1 to be resource, boolean given

this means that your query has an error

try to add this line before fetching the content

if (!$dbTaskRecords) {
    echo mysql_error();
    die;
}