Question

Im stuck on writing Word occurrence in a string.
I got some tip(in task notes) to use is compareToIgnoreCase. so I tried something like this:

splitwords = StringCont.split("\\s");
for(int i=0; i<splitwords.length; i++)
{
    if(splitwords[1].compareToIgnoreCase(splitwords[i]) == 0)
        splitcount++;
}

It is of course just what I can do and probably bad way. When I run the code, I get sometimes out of array exeption and sometimes it runs.
What is missing is: go through all words and check them and skip the words which were already counted.
I will be happy to get any help with this so can move along and understand how it can be coded. Thank you 🙂

Edit: It seems I did not explain the problem enough clearly, but I get nice answer about the map object which easily put together what I needed. I did not know about map.
So yea, I was trying to find the number of times every given word is found in the string.

tangens: it should mean-take the first word(where first whitespace is) splitwords[1] and compare it to all other words in string splitwords[i] and if it is 0(equals), then count++.

Esko: there indeed are white spaces like in sentence. But I still got this exeption.
I dont know why thru.

Answer 1

Store the words and their counts in a Map.

String[] words = string.toLowerCase().split("\\s+");
Map<String, Integer> wordCounts = new HashMap<String, Integer>();

for (String word : words) {
    Integer count = wordCounts.get(word);
    if (count == null) {
        count = 0;
    }
    wordCounts.put(word, count + 1);
}

Note that I called toLowerCase() before split() as you seem want to have case insensitivity.