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Editorial Team
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Editorial Team
Asked: May 14, 20262026-05-14T21:28:34+00:00 2026-05-14T21:28:34+00:00

I’m stuck with a problem how to check if a specific date is within

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I’m stuck with a problem how to check if a specific date is within allowed weekdays array in php. For example,

    function dateIsAllowedWeekday($_date,$_allowed)
    {
    if ((isDate($_date)) && (($_allowed!="null") && ($_allowed!=null))){
    $allowed_weekdays=json_decode($_allowed);
    $weekdays=array();

    foreach($allowed_weekdays as $wd){
    $weekday=date("l",date("w",strtotime($wd)));
    array_push($weekdays,$weekday);
    }
    if(in_array(date("l",strtotime($_date)),$weekdays)){return TRUE;}
    else {return FALSE;}
        }
        else {return FALSE;}
    }
 /////////////////////////////   
    $date="21.05.2010"; //actually is Friday (5)
    $wd="[0,1,2]"; //Sunday,Monday,Tuesday

    if(dateIsAllowedWeekday($date,$wd)){echo "$date is within $wd weekday values!";} 
    else{echo "$date isn't within $wd weekday values!"}

I have input dates formatted as “d.m.Y” and an array returned from database with weekday numbers (formatted as ‘Numeric representation of the day of the week’) like [0,1,2] – (Sunday,Monday,Tuesday).

The returned string from database can be “null”, so i check it too. Then, the isDate function checks whether date is a date and it is ok.

I want to check if my date, for example 21.05.2010 is an allowed weekday in this array. My function always returns TRUE and somehow weekday is always ‘Thursday’ and i don’t know why…

Is there any other ways to check this or what can be my error in the code above? thx

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  1. Editorial Team
    Editorial Team
    2026-05-14T21:28:34+00:00Added an answer on May 14, 2026 at 9:28 pm

    I’m not sure why you feel the need to convert the numeric day of the week into a string (eg “Sunday”) as you only return a boolean value in the end; anyway I’ve removed that part and the below code should function as expected:

    function dateIsAllowedWeekday($_date,$_allowed)
    {
      if ((isDate($_date)) && (($_allowed!="null") && ($_allowed!=null)))
      {
        $allowed_weekdays = json_decode($_allowed);
    
        if (in_array(date("w", strtotime($_date)), $allowed_weekdays))
        {
          return TRUE;
        }
      }
    
      return FALSE;
    }
    

    Tested with 21.05.2010 (returns false), and 11.05.2010 (returns true), with your allowed_weekdays as above ([0,1,2]).

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