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Editorial Team
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Asked: 2026-06-12T23:14:26+00:00

I’m stuck with a seemingly easy query, but couldn’t manage to get it working

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I’m stuck with a seemingly easy query, but couldn’t manage to get it working the last hours.

I have a table files that holds file names and some values like records in this file, DATE of creation (create_date), DATE of processing (processing_date) and so on. There can be multiple files for a create date in different hours and it is likely that they will not get processed in the same day of creaton, in fact it can even take up to three days or longer for them to get processed.

So let’s assume I have these rows, as an example:

create_date            | processing_date
------------------------------
2012-09-10 11:10:55.0  | 2012-09-11 18:00:18.0
2012-09-10 15:20:18.0  | 2012-09-11 13:38:19.0
2012-09-10 19:30:48.0  | 2012-09-12 10:59:00.0
2012-09-11 08:19:11.0  | 2012-09-11 18:14:44.0
2012-09-11 22:31:42.0  | 2012-09-21 03:51:09.0

What I want in a single query is to get a grouped column truncated to the day create_date with 11 additional columns for the differences between the processing_date and the create_date, so that the result should roughly look like this:

create_date   |   diff0days   | diff1days | diff2days | ... | diff10days
------------------------------------------------------------------------
2012-09-10    |       0             2           1       ...        0
2012-09-11    |       1             0           0       ...        1

and so on, I hope you get the point 🙂

I have tried this and so far it works getting a single aggregated column for a create_date with a difference of – for example – 3:

SELECT TRUNC(f.create_date, 'DD') as created, count(1) FROM files f WHERE TRUNC(f.process_date, 'DD') - trunc(f.create_date, 'DD') = 3 GROUP BY TRUNC(f.create_date, 'DD')

I tried combining the single queries and I tried sub-queries, but that didn’t help or at least my knowledge about SQL is not sufficient.

What I need is a hint so that I can include the various differences as columns, like shown above. How could I possibly achieve this?

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1 Answer

  1. Editorial Team

    That’s basically the pivoting problem:

    SELECT  TRUNC(f.create_date, 'DD') as created
,       sum(case TRUNC(f.process_date, 'DD') - trunc(f.create_date, 'DD')
                  when 0 then 1 end) as diff0days   
,       sum(case TRUNC(f.process_date, 'DD') - trunc(f.create_date, 'DD')
                  when 1 then 1 end) as diff1days   
,       sum(case TRUNC(f.process_date, 'DD') - trunc(f.create_date, 'DD')
                  when 2 then 1 end) as diff2days   
,       ...
FROM    files f 
GROUP BY 
        TRUNC(f.create_date, 'DD')
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