Question

I’m studying C++ from Schildt’s book and don’t quite understand what does he mean under third structure; Can somebody explain this ->

To access a specific structure within
an array of structures, you must index
the structure name. For example, to
display the on_hand member of the
third structure, you would write
cout << invtry[2].on_hand;

Some code:

struct type{
 char item[40];
 double cost;
 double retail;
 int on_hand;
 int lead_time;
}invtry[SIZE];

Answer 1

The third structure in an array of structures is the one placed in the third position in the array, i.e., the one with index 2.

In your (ugly) code, invtry is declared as an array (of size SIZE) of structures of type type. Hence invtry[0] is the first element, invtry[1] the second, and invtry[2] the third – assuming, of course, SIZE >= 3.

---

Normally, you would write:

struct type{
 char item[40];
 double cost;
 double retail;
 int on_hand;
 int lead_time;
};

const int SIZE = 500;

type invtry[SIZE];

This is synonymous to what you wrote, except for the definition of SIZE of course. But it leads to less confusion – in one part you say what a type (terrible name for the struct!) is – in other words, you define the type type. Later, you create an array of structs of type type, called invtry.

Doing this in the same line, as the author did, is simply awful – to my eyes.

Now you have an array of 500 structs. If “type” was “Product”, you would have an array representing 500 products. Each one with its item, cost, retail, etc.

To access the third struct in the array, write invtry[2]. to access its particular on_hand field, write invtry[2].on_hand. This has nothing to do with the specific position of on_hand in the layout of the defined type.

If you want the lead_time of the third structure, first access the third structure and then its lead_time member: invtry[2].lead_time.

Of course since type does not have a default (parameterless) constructor, the 500 products are uninitialized – you have garbage in them. But that is your problem.