Sign Up

Sign Up to our social questions and Answers Engine to ask questions, answer people’s questions, and connect with other people.

Have an account? Sign In

Have an account? Sign In Now

Sign In

Login to our social questions & Answers Engine to ask questions answer people’s questions & connect with other people.

Sign Up Here

Forgot Password?

Don't have account, Sign Up Here

Forgot Password

Lost your password? Please enter your email address. You will receive a link and will create a new password via email.

Have an account? Sign In Now

You must login to ask a question.

Forgot Password?

Need An Account, Sign Up Here

Please briefly explain why you feel this question should be reported.

Please briefly explain why you feel this answer should be reported.

Please briefly explain why you feel this user should be reported.

Sign InSign Up

The Archive Base

The Archive Base Logo The Archive Base Logo

The Archive Base Navigation

  • Home
  • SEARCH
  • About Us
  • Blog
  • Contact Us
Search
Ask A Question

Mobile menu

Close
Ask a Question
  • Home
  • Add group
  • Groups page
  • Feed
  • User Profile
  • Communities
  • Questions
    • New Questions
    • Trending Questions
    • Must read Questions
    • Hot Questions
  • Polls
  • Tags
  • Badges
  • Buy Points
  • Users
  • Help
  • Buy Theme
  • SEARCH
Home/ Questions/Q 666633
In Process

The Archive Base Latest Questions

Editorial Team
  • 0
Editorial Team
Asked: May 13, 20262026-05-13T23:50:23+00:00 2026-05-13T23:50:23+00:00

I’m sure there’s a clean way to do this, but I’m probably not using

  • 0

I’m sure there’s a clean way to do this, but I’m probably not using the right keywords for find it.

So let’s say I have a grid. Starting from a position on the grid, return all of the grid coordinates that fall within a given distance. So I call something like:

getCoordinates( currentPosition, distance )

And for each coordinate, starting from the initial position, add all cardinal directions, and then add the spaces around those and so forth until the distance is reached. I imagine that on a grid this would look like a diamond. The function would return that array of coordinates. Can someone point me to a routine that will do this efficiently ( I’m working in AS3, for what it’s worth )?

In the desired output, iteration 1 would be:

.x.
xxx
.x.

Iteration 2 would be:

..x..
.xxx.
xxxxx
.xxx.
..x..

Iteration 3:

...x...
..xxx..
.xxxxx.
xxxxxxx
.xxxxx.
..xxx..
...x...

and so on…

  • 1 1 Answer
  • 0 Views
  • 0 Followers
  • 0
Share
  • Facebook
  • Report

Leave an answer
Cancel reply

You must login to add an answer.

Forgot Password?

Need An Account, Sign Up Here

1 Answer

  • Voted
  • Oldest
  • Recent
  • Random
  1. Editorial Team
    Editorial Team
    2026-05-13T23:50:23+00:00Added an answer on May 13, 2026 at 11:50 pm

    Edit: Updated the algorithm to reflect what the OP wanted.

    Iteration 1:

    .x.
    xxx
    .x.
    

    Iteration 2:

    ..x..
    .xxx.
    xxxxx
    .xxx.
    ..x..
    

    …
    Iteration 4:

    ....x....
    ...xxx...
    ..xxxxx..
    .xxxxxxx.
    xxxxxxxxx
    .xxxxxxx.
    ..xxxxx..
    ...xxx...
    ....x....
    

    Clearly, you can determine the coordinates without iterating.

    If the starting point is (X, Y), and the iteration is n

    for(int i = x - n; i <= x + n; i++)
    {
        for(int j = y - n; j <= y + n; j++)
        {
            int dx = abs(i - x);
            int dy = abs(j - y);
            if(dx + dy <= n) //Produces a diamond, n+1 would produce a diamond with cut corners
            {
                //The point at (i, j) is within the marked area.
            }
        }
    }
    
    • 0
    • Reply
    • Share
      Share
      • Share on Facebook
      • Share on Twitter
      • Share on LinkedIn
      • Share on WhatsApp
      • Report

Sidebar

Related Questions

No related questions found

Explore

  • Home
  • Add group
  • Groups page
  • Communities
  • Questions
    • New Questions
    • Trending Questions
    • Must read Questions
    • Hot Questions
  • Polls
  • Tags
  • Badges
  • Users
  • Help
  • SEARCH

Footer

© 2021 The Archive Base. All Rights Reserved
With Love by The Archive Base

Insert/edit link

Enter the destination URL

Or link to existing content

    No search term specified. Showing recent items. Search or use up and down arrow keys to select an item.