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Home/ Questions/Q 1011241
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Editorial Team
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Editorial Team
Asked: May 16, 20262026-05-16T09:12:17+00:00 2026-05-16T09:12:17+00:00

I’m sure this is incredibly common with as OOP centered as Java is. In

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I’m sure this is incredibly common with as OOP centered as Java is. In java is there a way to make a base type variable that accepts all inherited subtypes? Like if I have;

class Mammal {...}
class Dog extends Mammal {...}
class Cat extends Mammal {...}

class ABC {
    private Mammal x;

    ABC() {
        this.x = new Dog();
        -or-
        this.x = new Cat();
    }
}

I need the variable to be able to accept any extended version too, but not in specific one extended kind.

There are some ways that I know, but don’t want to use. I could make an attribute for each subtype, then only have the one attribute actually used. Make an array and shove it in there.

Any other ideas or a way to get a “base class” type variable?


Ok since I know using polymorphic duck typing isn’t a great idea in Java, but since I don’t think I can avoid it. Is the only way to use subclass methods dynamically to re assign a casted version of the varible ie, I get an error with this;

Mammal x;
x = new Dog();
System.out.println(x.getClass());
x.breath();
if (x instanceof Dog) {
  x.bark();
} else if (x instanceof Cat) {
  x.meow();
}

Saying symbol not found, however this works;

Mammal x;
x = new Dog();
System.out.println(x.getClass());
x.breath();
if (x instanceof Dog) {
  Dog d = (Dog) x;
  d.bark();
} else if (x instanceof Cat) {
  Cat c = (Cat) x;
  c.meow();
}

That last one the only way to do it?

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-16T09:12:18+00:00Added an answer on May 16, 2026 at 9:12 am

    If you have the following:

    class Mammal {...}
    class Dog extends Mammal {...}
    class Cat extends Mammal {...}
    

    Then Dog is a subtype of Mammal. Cat is also a subtype of Mammal. This type polymorphism does in fact allow you to do the following:

    Mammal x;
    x = new Dog(); // fine!
    x = new Cat(); // also fine!
    

    If in fact later there’s the following:

    class Platypus extends Mammal {...} // yes it's true!
    

    Then you can also do:

    x = new Platypus(); // fine!
    

    This polymorphic subtyping relationship is one of the basic tenets of object-oriented programming.

    See also

    • Java Tutorials/Object-Oriented Programming Concepts
    • Wikipedia/Polymorphism in object-oriented programming

      Subtype polymorphism, almost universally called just polymorphism in the context of object-oriented programming, is the ability of one type, A, to appear as and be used like another type, B


    On instanceof type comparison operator

    Suppose we have the following:

    class Mammal { void lactate(); }
    class Dog extends Mammal { void bark(); }
    class Cat extends Mammal { void meow(); }
    

    Then you can use instanceof type comparison operator (§15.20.2) to do something like this:

    Mammal x = ...;
    
    if (x instanceof Dog) {
       Dog d = (Dog) x;
       d.bark();
    } else if (x instanceof Cat) {
       Cat c = (Cat) x;
       c.meow();
    }
    if (x != null) {
       x.lactate();
    }
    

    There are also ways to do this without if-else; this is just given as a simple example.

    Note that with appropriate design, you may be able to avoid some of these kinds of subtype differentiation logic. If Mammal has a makeSomeNoise() method, for example, you can simply call x.makeSomeNoise().

    Related questions

    • When should I use the Visitor Design Pattern? – sometimes used to simulate double dispatch

    On reflection

    If you must deal with new types not known at compile-time, then you can resort to reflection. Note that for general applications, there are almost always much better alternatives than reflection.

    See also

    • Java Technical Articles/Advanced Language Topics/Reflection
    • Effective Java 2nd Edition, Item 53: Prefer interfaces to reflection
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