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Asked: 2026-06-17T07:15:14+00:00

I’m taking a security course and am having trouble understanding this code due to

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I’m taking a security course and am having trouble understanding this code due to a lack of understanding of the C programming language.

printf  ("%08x.%08x.%08x.%08x|%s|");

I was told that this code should move along the stack until a pointer to a function is found.

I thought the . was just an indicator of precision of output, so I don’t know what this means in this context since there are indicators of precision?

Also, I don’t understand what the | means, and I can’t find it in the C documentation.

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1 Answer

  1. Editorial Team

    The symbols have no special meaning here since they are outside of a format specifier, they are simply output literally. Note however that you haven’t provided all the arguments that printf expects so it will instead print 5 values that happen to be on the stack.

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