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Editorial Team
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Asked: 2026-06-15T12:09:01+00:00

i’m transforming all xml elements into xhtml <div> tags using a recursive template match.

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i’m transforming all xml elements into xhtml <div> tags using a recursive template match.

basically, i wish to turn the element name() into a class name, ie . <div class="name()">value</div>

i used the following:

<body>
    <xsl:apply-templates />
</body>

<xsl:template match="*">
  <div class="{name()}"><xsl:value-of select="."/>
  <xsl:apply-templates select="*"/>
  </div>
</xsl:template>

it works quite well, except it plucks out the values on parent tags.
for example, this xml

  <TotalPayments>
    <Amount>26.96</Amount>
    <TaxableAmount>26.96</TaxableAmount>
    <TaxAmount>0.00</TaxAmount>
    <ShippingAmount>0.00</ShippingAmount>
  </TotalPayments>

turns into:

<div class="TotalPayments">
        26.96
        26.96
        0.00
        0.00
  <div class="Amount">26.96</div>
  <div class="TaxableAmount">26.96</div>
  <div class="TaxAmount">0.00</div>
  <div class="ShippingAmount">0.00</div>
</div>

and i only want

<div class="TotalPayments">
  <div class="Amount">26.96</div>
  <div class="TaxableAmount">26.96</div>
  <div class="TaxAmount">0.00</div>
  <div class="ShippingAmount">0.00</div>
</div>

And it gets worse and worse up the tree. the root has all that too.

so should i do a test or can one select only certain types.
i also tried matching

* | text()
* | node()

thanks.

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1 Answer

  1. Editorial Team

    Simply remove the <xsl:value-of select="."/> and then change the <xsl:apply-templates select="*"/> to <xsl:apply-templates/>. That way the default template for text node children will output them (and the elements children are processed the same as before).

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