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Home/ Questions/Q 8609837
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Editorial Team
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Editorial Team
Asked: June 12, 20262026-06-12T03:58:32+00:00 2026-06-12T03:58:32+00:00

I’m trying to access the Twitter stream which I had working previously while improperly

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I’m trying to access the Twitter stream which I had working previously while improperly using Tweepy. Now that I understand how Tweepy is intended to be used I wrote the following Stream.py module. When I run it, I get error code 401 which tells me my auth has been rejected. But I had it working earlier with the same consumer token and secret. Any ideas?

from tweepy.streaming import StreamListener
from tweepy import OAuthHandler
from tweepy import Stream
from tweepy import TweepError
from tweepy import error

#Removed. I have real keys and tokens
consumer_key = "***" 
consumer_secret = "***"
access_token="***"
access_token_secret="***"

class CustomListener(StreamListener):
    """ A listener handles tweets are the received from the stream. 
        This is a basic listener that just prints received tweets to stdout."""

    def on_status(self, status):
        # Do things with the post received. Post is the status object.
        print status.text
        return True

    def on_error(self, status_code):
        # If error thrown during streaming.
        # Check here for meaning: 
        # https://dev.twitter.com/docs/error-codes-responses
        print "ERROR: ",; print status_code
        return True

    def on_timeout(self):
        # If no post received for too long
        return True

    def on_limit(self, track):
        # If too many posts match our filter criteria and only a subset is
        # sent to us
        return True

    def filter(self, track_list):
        while True:
            try:
                self.stream.filter(track=track_list)
            except error.TweepError as e:
                raise TweepError(e)

    def go(self):
        listener = CustomListener()
        auth = OAuthHandler(consumer_key, consumer_secret)
        self.stream = Stream(auth,listener,timeout=3600)
        listener.filter(['LOL'])

if __name__ == '__main__':
    go(CustomListener)
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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-06-12T03:58:33+00:00Added an answer on June 12, 2026 at 3:58 am

    For anyone who happens to have the same issue, I should have added this line after auth was initialized:

    auth.set_access_token(access_token, access_token_secret)
    
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