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Home/ Questions/Q 927065
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Editorial Team
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Editorial Team
Asked: May 15, 20262026-05-15T19:47:28+00:00 2026-05-15T19:47:28+00:00

im trying to achieve the following, in php i have a form like this:

  • 0

im trying to achieve the following, in php i have a form like this:

<form method="post"  id="form_1" action="php.php">
<input type="submit" value="add" name="sub"/>
<input type="submit" value="envoi" name="sub"/>
</form>

the form action file is:

<?php

if( $_POST["sub"]=="add"){  ?>

 <script>
 alert("")
 </script>
<?php  echo "ZZZZZZ";   ?>

<?php } ?>

so this means if i press sub with value add an alert prompt will come up, how can i do the same thing(differentiate both submit) but using a Ajax request:

the following code so does not work:

 $(function(){
      $('form#form_1').submit(function(){
var _data= $(this).serialize()
$.ajax({
        type: 'POST',
        url: "php.php?",
        data:_data,
        success: function(html){
         $('div#1').html(html)

          }
     })
})
  })
  </script>
</head>

<body>
<div id="1" style="width: 100px;height: 100px;border: 1px solid red"></div>

<form method="post"  id="form_1" action="javascript:;">
<input type="submit" value="add" name="sub"/>
<input type="submit" value="envoi" name="sub"/>
</form>
</body>
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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-15T19:47:29+00:00Added an answer on May 15, 2026 at 7:47 pm

    You could put the event handler on the buttons instead of on the form. Get the parameters from the form, and then add a parameter for the button, and post the form. Make sure the handler returns “false”.

    $(function() {
      $('input[name=sub]').click(function(){
        var _data= $('#form_1').serialize() + '&sub=' + $(this).val();
        $.ajax({
          type: 'POST',
          url: "php.php?",
          data:_data,
          success: function(html){
             $('div#1').html(html);
          }
        });
        return false;
      });
    });
    

    You have to explicitly add the “sub” parameter because jQuery doesn’t include those when you call “serialize()”.

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