Question

I’m trying to apply a transform with java (currentXSLT.transform(xmlFile, outputFile);) But I’m getting escaped text. I need the characters that are being scaped, from the text of the XML.

So far I have tried with this:

    <?xml version="1.0" encoding="utf-8"?>
    <xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform" >
      <xsl:output method="xml" indent="no" omit-xml-declaration="yes"/>
      <xsl:strip-space elements="*"/>

      <xsl:template match="@* | node()">
        <xsl:copy>
            <xsl:apply-templates select="@*|node()"/>
        </xsl:copy>
      </xsl:template>

      <xsl:template match="text()">
        <xsl:copy>
            <xsl:value-of select="." disable-output-escaping="yes"/>
        </xsl:copy>
      </xsl:template>
    </xsl:stylesheet>

But it doesn’t seem to work.

Any ideas?

Thanks.

Answer 1

At the end, I couldn’t do it with plain xslt, I had to use apache commons in order to unescape the text. Since it was a business requirement to keep the invalid signs, I had to find a workaround:

StringWriter stringWriter = new StringWriter();
transformer.transform(xmlFile, new StreamResult(stringWriter));
String xmlOutput = stringWriter.getBuffer().toString();
xmlOutput = StringEscapeUtils.escapeXml(xmlOutput);