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Home/ Questions/Q 6131651
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Editorial Team
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Editorial Team
Asked: May 23, 20262026-05-23T17:00:09+00:00 2026-05-23T17:00:09+00:00

I’m trying to break down an integer with C on an 8-bit microcontroller (a

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I’m trying to break down an integer with C on an 8-bit microcontroller (a PIC) into its ASCII equivalent characters.

For example:
convert 982 to ‘9’,’8′,’2′

Everything I’ve come up with so far seems pretty brute force. This is the main idea of what I’m basically doing right now:

if( (10 <= n) && (n < 100) ) {
// isolate and update the first order of magnitude
digit_0 = (n % 10);
// isolate and update the second order of magnitude
switch( n - (n % 10) ) {
  case 0:
    digit_1 = 0;
    break;
  case 10:
    digit_1 = 1;
    break;

…

And then I have another function to just add 0b00110000 (48decimal) to each of my digits.

I’ve been having trouble finding any C function to do this for me or doing it well myself.

Thanks in advance for any help!

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  1. Editorial Team
    Editorial Team
    2026-05-23T17:00:10+00:00Added an answer on May 23, 2026 at 5:00 pm

    To do it yourself you need to perform the operations which are demonstrated with the sample code below:

    #include <stdio.h>
    
    int main (void)
    {
      unsigned int x = 512;
      int base_val = 10, digit, i = 0, n = 0;
      char x_str[32], t;
    
      printf ("\nEnter an unsigned number: ");
      scanf ("%u", &x);
    
      printf ("\nEnter base: ");
      scanf ("%d", &base_val);
    
      /* Chop the digits in reverse order and store in `x_arr`
       * the interpretation of the digits are made in base value
       * denoted by `base_val`
       */
    
      while (x)
      {
        digit = x % base_val;
        x /= base_val;
        if (digit < 10)
          x_str[n++] = digit + '0';
        else
          x_str[n++] = digit + 'A' - 10;  /* handle base > 9 */
      }
    
      /* Terminate string */
      x_str[n] = '\0';
    
      /* Reverse string */
      for (i=0; i<n/2; i++)
      {
        t = x_str[i];
        x_str[i] = x_str[n-i-1];
        x_str[n-i-1] = t;
      }
      printf ("\n%s\n", x_str);
    
      return 0;
    }
    

    The while loop will chop out the digits from the integer in a given base and feed the digits in reverse order in an array. The inner if - else handles base more than 9, and places uppercase alphabets when a digit value is greater than 10. The for loop reverses the string and gets the chopped number into string in forward order.

    You need to adjust the size of x_str array as per your max capability. Define a macro for it. Note the above code is only for unsigned integers. For signed integers you need to first check if it is below 0, then add a ‘-‘ sign in x_str and then print the magnitude ie. apply the above code with -x . This can also be done by checking the sign bit, by masking, but will make the process dependent on storage of integer.

    The base_val is the base in which you want to interpret the numbers.

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