Question

I’m trying to build a function that accepts an array in the following manner:

int inCommon = findCommon({54,56,2,10}, 4);  int findCommon(int nums[], int len){   for(int i=0; i<len; i++)  cout<<nums[i]<<endl;   return 1; }  

Note, that’s not actually what my function does, but I do loop through the array. I’m just trying to determine if it’s possible to pass an array like {54,56,2,10} instead of having to create an array and pass it? (like this:

int theArray[]= {54,56,2,10}; int inCommon = findCommon(theArray,4); 

Answer 1

This is not possible at the time. However, in the next C++ standard C++0x, this will be done using initalizer lists:

int findCommon(std::initializer_list<int> nums) {     std::initializer_list<int>::iterator it;     for (it = nums.begin() ; it != nums.end() ; ++it)     {         std::cout << *it << std::endl;       }     return 1; } 

See this presentation from Bjarne Stroustrup, and this article from Wikipedia

If you want to try C++0x features, you can check the last versions of gcc, that supports some of them.