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Home/ Questions/Q 3338320
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Editorial Team
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Editorial Team
Asked: May 18, 20262026-05-18T00:21:39+00:00 2026-05-18T00:21:39+00:00

I’m trying to build a list of checkboxes by using jQuery.tmpl It’ll list an

  • 0

I’m trying to build a list of checkboxes by using jQuery.tmpl
It’ll list an array of items with a checkbox near them, and I want to check some of these checkboxes parametrically…

The template code is:

<ul>
{{each(i,val) Values}}
    <li>
        <input type="checkbox" {{if $.inArray(i, Default) != -1}} checked="checked"{{/if}}>
        <em>${val}</em>
    </li>
{{/each}}
</ul>

and the template definition:

<script type="text/javascript">
    $(document).ready(function() {
        $('#tpl_selector').tmpl({
            Default: [1,2],
            Values: {
                1: 'Item 1',
                2: 'Item 2',
                3: 'Item 3'
            }
        }).appendTo('#area');

    });
</script>

So the Item 1 and Item 2 should be checked in this case. The list is created with no problem, but {{if $.inArray(i, Default) != -1}} checked="checked"{{/if}} part is not working.

However, when I replace ‘i’ with a number, it works:
{{if $.inArray(1, Default) != -1}} checked="checked"{{/if}}

I doesn’t make any sense at all… Do you have any suggestions?

Another logic to fill the checkboxes is ok too, like I don’t know smt. like a callback function after the rendering completes or else…

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-18T00:21:40+00:00Added an answer on May 18, 2026 at 12:21 am

    The problem

    In JavaScript objects, the key is always a string. Your Default array contains numbers, but the “needle” you’re passing in (i) is a string, so $.inArray will always return false,.

    jsfiddle 0

    The solutions

    Any one of these will work:

    1. Make Values a proper array, rather than an object “indexed” by strings containing numbers.
      • jsfiddle 1 (Note the zero-based indexing!)
    2. Make Defaults an array of strings.
      • jsfiddle 2
    3. parseInt() the Values key (i) when you pass it to $.inArray(). I think this is an ugly fix.
      • jsfiddle 3

    Oh, and welcome to Stack Overflow!

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