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Home/ Questions/Q 7550257
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Editorial Team
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Editorial Team
Asked: May 30, 20262026-05-30T10:09:58+00:00 2026-05-30T10:09:58+00:00

I’m trying to build a litle gam for android GSMs. I hava lots of

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I’m trying to build a litle gam for android GSMs. I hava lots of units and all of them have destinations. To calculate destination I’m using a function called CalDes. This function CalDes is calculating my unit’s speed. So I’m sending some variables into which I have to edit and use em again. For this I have to send these variables with reference. Here is a simple for C++ How to do that in java?

void swap(SomeType& arg1, Sometype& arg2) {
    SomeType temp = arg1;
    arg1 = arg2;
    arg2 = temp;
}
...
SomeType var1 = ...; // value "A"
SomeType var2 = ...; // value "B"
swap(var1, var2); // swaps their values!
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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-30T10:09:59+00:00Added an answer on May 30, 2026 at 10:09 am

    Java doesn’t have pass-by-reference at all. You have a couple of options:

    1. Pass the data in an array:

      void swap(SomeType[] args) {
          SomeType temp = args[0];
          args[0] = args[1];
          args[1] = temp;
      }
      

      …but using it is a pain in the calling code:

      SomeType a = ...;
      SomeType b = ...;
      SomeType[] args = new SomeType[] { a, b };
      swap(args);
      a = args[0];
      b = args[1];
      
    2. Create an object that has public SomeType members, and pass in the object reference.

      void swap(SomeTypeContainer c) {
          SomeType temp = c.a;
          c.a = c.b;
          c.b = temp;
      }
      

      Which is very similar to #1, but probably more convenient to work with from calling code.

      SomeTypeContainer c = new SomeTypeContainer(/* ... something that creates a and b ... */);
      // Use c.a and c.b directly
      swap(c);
      // Use c.a and c.b directly, they're now swapped
      
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