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Editorial Team
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Asked: 2026-06-02T18:20:54+00:00

I’m trying to build a mobile application with PhoneGap and jQuery Mobile . In

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I’m trying to build a mobile application with PhoneGap and jQuery Mobile . In my app I have a page where is a link to PHP file which updates MYSQL and heads to next page. But with PhoneGap I need to have all the PHP files on external server so I can’t my current solution on this application.

This is the PHP that I use to update MYSQL

<?php

$var = @$_GET['id'] ;

$con = mysql_connect("localhost","username","abc123");
if (!$con)
  {
  die('Could not connect: ' . mysql_error());
  }

mysql_select_db("database", $con);

mysql_query("UPDATE table SET condition=true
WHERE ID= \"$var\" ");

header('Location: http://1.2.3.4/test');

mysql_close($con);
?>

So how can I run this PHP when user clicks a button? With jQuery/AJAX i suppose?

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1 Answer

  1. Editorial Team

    Lets say the above PHP code is in file, update.php. Then you can use the following code – 

    <head>
<script src="jquery.js"></script>
<script>
  function UpdateRecord(id)
  {
      jQuery.ajax({
       type: "POST",
       url: "update.php",
       data: 'id='+id,
       cache: false,
       success: function(response)
       {
         alert("Record successfully updated");
       }
     });
 }
</script>
</head>
<body>
<input type="button" id="button_id" value="Update" onClick="UpdateRecord(1);">
</body>

    Just pass a valid id in the UpdateRecord function. Put your PHP code in update.php file. Just to be on a safer side, in your PHP code replace $var = @$_GET['id'] ; with $var = @$_POST['id'] ; and check if this works for you

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