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Home/ Questions/Q 8996589
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Editorial Team
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Editorial Team
Asked: June 15, 20262026-06-15T23:46:28+00:00 2026-06-15T23:46:28+00:00

I’m trying to build a regex that will match BBCode attributes. I want it

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I’m trying to build a regex that will match BBCode attributes. I want it to match attributes without quotation marks (attr=value) and also with them (attr="value"), but don’t match if there’s only one mark (attr="value or attr=value").

I managed to get close to a solution with this regex /\[size\=((?=")"(.*?)"|([^"]*))\](.*?)\[\/size\]/is (for size tags), using a lookahead, but it places the match for the quoted and unquoted attributes on different indexes. Here’s a scheme:

+-----------------------+----------+----------+----------+----------+
| Input                 | Match #1 | Match #2 | Match #3 | Match #4 |
+-----------------------+----------+----------+----------+----------+
| [size="7"]txt[/size]  | "7"      | 7        |          | txt      |
+-----------------------+----------+----------+----------+----------+
| [size=7]txt[/size]    | 7        |          | 7        | txt      |
+-----------------------+----------+----------+----------+----------+

While this is not a major issue, I’d like to know if there’s any wya to match them to the same index.

Background Info:

Basically, I’m working on improving a BBCode parser. As for now, it only allows attributes to be placed without quotation marks ". Now, that brings a whole lot of limitations to it, so I’m adding support to quoted attributes. Problem is I can’t break backwards compatibility, so I gotta come up with something that works for both cases.

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  1. Editorial Team
    Editorial Team
    2026-06-15T23:46:29+00:00Added an answer on June 15, 2026 at 11:46 pm

    Since the group which matches your first case must be distinct from the group matching the second case, I don’t believe there’s any way to get them to match to same index/group.

    It’s not unusual to see code working around this like the following though:

    attr = matches[1] or matches[2]
    

    Since you can know for sure that at most 1 of those elements are non-empty, the or logic works.

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