Question

I’m trying to build a report that will look like this:

      jan feb mar apr may jun jul ago sep oct nov dec food   0   1   1   2   0   0   3   1   0   0   1   1 car    1   0   0   0   1   2   1   0   1   2   3   4 home   0   0   1   2   2   2   5   1   2   4   0   0 other  0   0   0   0   0   0   0   0   0   0   0   0 

I have two tables: t_item and t_value. t_item has 2 columns: itemID and itemName. t_value has 3 columns: itemID, value, date.

With the following query I can generate a list with all the itens, even with the empty ones.

SELECT t_item.itemID, ISNULL(SUM(t_value.value), 0) AS value FROM t_value RIGHT OUTER JOIN t_item ON t_value.itemID = t_item.itemID GROUP BY t_item.itemID 

But, if I try to include a MONTH column (as follows) the result will show only the items with values…

SELECT t_item.itemID, ISNULL(SUM(t_value.value), 0) AS value, MONTH(date) AS date FROM t_value RIGHT OUTER JOIN t_item ON t_value.itemID = t_item.itemID GROUP BY t_item.itemID, MONTH(date) 

Is it possible to do it? How do I include into the results the itens with no values and group then by month?

TIA,

Bob

Answer 1

WITH    calendar(mon) AS         (         SELECT  1         UNION ALL         SELECT  mon + 1         FROM    calendar         WHERE   mon < 12         ) SELECT  itemID, mon, SUM(value) FROM    calendar c, t_item i LEFT OUTER JOIN         t_value v ON      v.itemID = i.itemID         AND MONTH(date) = mon GROUP BY         i.itemID, mon