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Home/ Questions/Q 7540897
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Editorial Team
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Editorial Team
Asked: May 30, 20262026-05-30T07:45:15+00:00 2026-05-30T07:45:15+00:00

I’m trying to build a table that is 5×6 dynamically using PHP. Right now

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I’m trying to build a table that is 5×6 dynamically using PHP. Right now I’m getting my table to be 1×30. I’m probably missing an if statement or something but just can’t figure it out. A little help would be great.

 $data = mysql_query("SELECT * FROM product") 
 or die(mysql_error());
 $info = mysql_fetch_array( $data );
 print "<table border cellpadding='0' cellspacing='0'>";
 while($info = mysql_fetch_array( $data )) 
 { 
 Print "<tr><td>".$info['name'] . "  <br /><img src=".$info['pictureURL'] . " /></td></tr>"; 
 }

print "</table>";

Here is a Demo of what it looks like http://nova.it.rit.edu/~mpb8676/FinalProject/compare.php

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-30T07:45:16+00:00Added an answer on May 30, 2026 at 7:45 am

    You are printing a new row for each record with this line:

    Print "<tr><td>".$info['name'] . "  <br /><img src=".$info['pictureURL'] . " /></td></tr>";
    

    If you want a 5×6 table, then you’ll have to add in a column counter:

    $data = mysql_query("SELECT * FROM product") 
    or die(mysql_error());
    $info = mysql_fetch_array( $data );
    print "<table border cellpadding='0' cellspacing='0'>";
    $numCols = 5;   // Max number of columns
    $colCount = 0;  // Current column count (the counter)
    while($info = mysql_fetch_array( $data )) 
    { 
        if ($colCount == 0) {
            Print "<tr>";
        }
    
        Print "<td>".$info['name'] . "  <br /><img src=".$info['pictureURL'] . " /></td>";
    
        $colCount++;
    
        if ($colCount >= $numCols) {
            Print "</tr>";
            $colCount = 0;
        }
    }
    
    print "</table>";
    

    There are definitely more efficient ways to go about this, but I tried to keep your code in tact so you’d better understand what your issue was.

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