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Home/ Questions/Q 7163589
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Editorial Team
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Editorial Team
Asked: May 28, 20262026-05-28T13:55:41+00:00 2026-05-28T13:55:41+00:00

i’m trying to build an array from an Object in PHP. I only want

  • 0

i’m trying to build an array from an Object in PHP. I only want certain properties from the object but I don;t know what they will be each time. The names of the properties I need are stored in an array. Here is how my code works currently:

// Hard-coded attributes 'colour' and 'size'

while ($objVariants->next())
{   
    $arrVariants[] = array
    (   
        'pid' => $objVariants->pid,
        'size' => $objVariants->size,
        'colour' => $objVariants->colour,
        'price' => $objVariants->price                                                      
    );        
}

Instead of hard coding the attributes (colour and size) I want to use variables, this is because it may not always be colour and size depending on what the user has set in the CMS. For example:

$arrVariantAttr = $this->getVariantAttr(); // Get the names of the custom variants and put them in an array e.g colour, size

while ($objVariants->next())
{   
    $arrVariants[] = array
    (   
        'pid' => $objVariants->pid,

        foreach($arrVariantAttr as $attr)
        {
            $attr['name'] => $objVariants-> . $attr['name']; // Get each variant out of the object and put into an array
        }

        'price' => $objVariants->price                                                      
    );        
}

The above code doesn’t work, but hopefully it illustrates what i’m trying to do. Any help would be appreciated, thank you!

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-28T13:55:42+00:00Added an answer on May 28, 2026 at 1:55 pm

    Try something like this:

    $arrVariants[] = Array(
      'pid' => $objVariants->pid,
      'price' => $objVariants->price
    );
    
    while( $objVariants->next() )
    {
      foreach( $arrVariantAttr as $attr )
      {
        end($arrVariants)[$attr['name']] = $objVariants->$attr['name'];
      }
    }
    
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