Question

I’m trying to capture the last digits in this line in a regex group:

The input:

9 Power_On_Hours          0x0032   099   099   000    Old_age   Always       -       54654

My pattern:

/Power_On_Hours.+Always\s.+([0-9]{1,5})/

I just can’t seem to get it to capture “54654”, it’s returning undef 🙁

Answer 1

Actually, that capture group should grab ‘4’, not undef. Your final .+ will eat up everything until the last digit and then capture that to $1. This revision captures all the digits to $1:

/Power_On_Hours.+Always\s.+?(\d{1,5})/

The ? makes the .+ non-greedy, so it will match characters up to when the digits (\d) start to match.