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Home/ Questions/Q 7942221
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Editorial Team
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Editorial Team
Asked: June 3, 20262026-06-03T23:54:15+00:00 2026-06-03T23:54:15+00:00

I’m trying to catch an input error – where the only valid input is

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I’m trying to catch an input error – where the only valid input is an integer.

If a non integer is input, I want it to return to the start of func and try again:

def setItorator():
 try:
  iterationCap = int(raw_input("Please enter the number of nibbles you want to make: "))
  print "You will make", iterationCap, "nibbles per file"
 except ValueError:
  print "You did not enter a valid integer, please try again"
  setItorator()
 return iterationCap 

if __name__ == "__main__":
 iterationCap = setItorator()

This method works if the first input is valid, and returns to the start of the func if a non valid input is made, but it does not seem to pass the correct valid back to the main func. I checked in the sub func that it sees the correct variable, and of the correct type (int) and it does appear to, but I get an error:

UnboundLocalError: local variable 'iterationCap' referenced before assignment  

I do not see this error if the first input is valid (e.g. “10”) only if the first input is not valid (e.g. “a” followed by “10”)

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  1. Editorial Team
    Editorial Team
    2026-06-03T23:54:17+00:00Added an answer on June 3, 2026 at 11:54 pm

    Try something like this.

    while True:
       try:
        i = int(raw_input("Enter value "))
        break
       except ValueError:
        print "Bad input"
    
    print "Value is ",i
    

    Your current approach will recursively call your function for every error which is not a good practice. The error is because inside your exception handler block, you’re not defining iterationCap.

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