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Home/ Questions/Q 8799159
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Editorial Team
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Editorial Team
Asked: June 14, 20262026-06-14T00:15:12+00:00 2026-06-14T00:15:12+00:00

I’m trying to catch error 60 and continue the execution of my script, here

  • 0

I’m trying to catch error 60 and continue the execution of my script, here is what I am doing at the moment :

import urllib2
import csv
from bs4 import BeautifulSoup


matcher = csv.reader(open('matcher.csv', "rb" ))

for i in matcher:
    url = i[1]
    if len(list(url)) > 0:
        print url
        try:
            soup = BeautifulSoup(urllib2.urlopen(url,timeout=10))   

        except urllib2.URLError, e:
            print ("There was an error: %r" % e)

It returns this :

Traceback (most recent call last): File “debug.py”, line 13, in

soup = BeautifulSoup(urllib2.urlopen(url,timeout=10)) File “/Library/Frameworks/Python.framework/Versions/2.7/lib/python2.7/urllib2.py”,
line 126, in urlopen
return _opener.open(url, data, timeout) File “/Library/Frameworks/Python.framework/Versions/2.7/lib/python2.7/urllib2.py”,
line 400, in open
response = self._open(req, data) File “/Library/Frameworks/Python.framework/Versions/2.7/lib/python2.7/urllib2.py”,
line 418, in _open
‘_open’, req) File “/Library/Frameworks/Python.framework/Versions/2.7/lib/python2.7/urllib2.py”,
line 378, in _call_chain
result = func(*args) File “/Library/Frameworks/Python.framework/Versions/2.7/lib/python2.7/urllib2.py”,
line 1207, in http_open
return self.do_open(httplib.HTTPConnection, req) File “/Library/Frameworks/Python.framework/Versions/2.7/lib/python2.7/urllib2.py”,
line 1180, in do_open
r = h.getresponse(buffering=True) File “/Library/Frameworks/Python.framework/Versions/2.7/lib/python2.7/httplib.py”,
line 1030, in getresponse
response.begin() File “/Library/Frameworks/Python.framework/Versions/2.7/lib/python2.7/httplib.py”,
line 407, in begin
version, status, reason = self._read_status() File “/Library/Frameworks/Python.framework/Versions/2.7/lib/python2.7/httplib.py”,
line 365, in _read_status
line = self.fp.readline() File “/Library/Frameworks/Python.framework/Versions/2.7/lib/python2.7/socket.py”,
line 447, in readline
data = self._sock.recv(self._rbufsize) socket.timeout: timed out

How would I catch this error and “continue” ?

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-06-14T00:15:13+00:00Added an answer on June 14, 2026 at 12:15 am

    You can try except Exception as e: to catch all errors. However remember this catches all errors and should be avoided if you want to catch only specific errors.

    Edit:
    you can check the exception type by doing:

    except Exception as e:
        exc_type, exc_obj, exc_tb = sys.exc_info()
        fname = os.path.split(exc_tb.tb_frame.f_code.co_filename)[1]      
        print(exc_type, fname, exc_tb.tb_lineno)
    
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