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Editorial Team
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Asked: 2026-06-03T03:08:10+00:00

I’m trying to check if a gravatar exists. When I try the approach recommended

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I’m trying to check if a gravatar exists. When I try the approach recommended in earlier questions, I get an error ” Warning: get_headers() [function.get-headers]: This function may only be used against URLs” Anyone seen this or see the error in my code? PS I do not want to specify a default image for gravatar to serve as there could be more than one default possibilities if no gravatar exits.

Also, I found a reference to error possibly being related to my ini file which I don’t think my host gives me access to. If so, is there an alternative to getheaders? Many thanks.

$email = $_SESSION['email'];
$email= "person@gmail.com"; //for testing
$gravemail = md5( strtolower( trim( $email ) ) );
$gravsrc = "http://www.gravatar.com/avatar/".$gravemail;
$gravcheck = "http://www.gravatar.com/avatar/".$gravemail."?d=404";
$response = get_headers('$gravcheck');
echo $response;
exit;
if ($response != "404 Not Found"..or whatever based on response above){
$img = $gravsrc;
}
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1 Answer

  1. Editorial Team

    Observation

    A. get_headers('$gravcheck'); would not work because of use of single quote '

    B. calling exit; would terminate script prematurely

    C. $response would return an array you can not use echo to print the information use print_r insted

    D. $response != "404 Not Found" would not work because $response is array

    This is the proper way to do it :

    $email= "person@gmail.com"; //for testing
$gravemail = md5( strtolower( trim( $email ) ) );
$gravsrc = "http://www.gravatar.com/avatar/".$gravemail;
$gravcheck = "http://www.gravatar.com/avatar/".$gravemail."?d=404";
$response = get_headers($gravcheck);
print_r($response);
if ($response[0] != "HTTP/1.0 404 Not Found"){
    $img = $gravsrc;
}
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