Question

i’m trying to check the output of a cURL.

<?php

    $ch = curl_init();
    curl_setopt($ch, CURLOPT_URL,"https://blablabla.com");
    curl_setopt($ch, CURLOPT_RETURNTRANSFER,1);
    $curlresult=curl_exec ($ch);
      curl_close ($ch);



    if ($curlresult == "OK") {
        $result = "The curl action was succeeded! (OUTPUT of curl is: ".$curlresult.")";
    } else {
        $result = "The curl action has FAILED! (OUTPUT of curl is: ".$curlresult.")";
    }

echo $result;

?>

The URL (https://blablabla.com) is a URL that just displays OK.
So, using the code, I would expect to see

“The curl action was succeeded! (OUTPUT of curl is: OK)”

But, what I do get is:

The curl action has FAILED! (OUTPUT of curl is: OK )

I guess i’m making some stupid mistake. How can I check if https://blablabla.com contains “OK”?

Thanks!

Answer 1

You may be getting extra white spaces before or after the OK or other characters.

I suggest doing what the people above suggested by testing what is exactly inside the array with var_dump($curlresult); or print_r($curlresult);

But alternatively you could instead of matching that $curlresult equals only “OK”, you could test if $curlresult contains “OK” inside of it.

<?php

    $ch = curl_init();
    curl_setopt($ch, CURLOPT_URL,"https://blablabla.com");
    curl_setopt($ch, CURLOPT_RETURNTRANSFER,1);
    $curlresult=curl_exec ($ch);
      curl_close ($ch);



    if (preg_match("/OK/i", $curlresult)) {
        $result = "The curl action was succeeded! (OUTPUT of curl is: ".$curlresult.")";
    } else {
        $result = "The curl action has FAILED! (OUTPUT of curl is: ".$curlresult.")";
    }

echo $result;

?>