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Home/ Questions/Q 499699
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Editorial Team
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Editorial Team
Asked: May 13, 20262026-05-13T06:00:44+00:00 2026-05-13T06:00:44+00:00

I’m trying to come up with a regular expression that will match a fraction

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I’m trying to come up with a regular expression that will match a fraction (1/2) but not a date (5/5/2005) within a string. Any help at all would be great, all I’ve been able to come up with is (\d+)/(\d+) which finds matches in both strings. Thanks in advance for the help.

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  1. Editorial Team
    Editorial Team
    2026-05-13T06:00:44+00:00Added an answer on May 13, 2026 at 6:00 am

    Assuming PCRE, use negative lookahead and lookbehind:

    (?<![\/\d])(\d+)\/(\d+)(?![\/\d])
    

    A lookahead (a (?=) group) says “match this stuff if it’s followed by this other stuff.” The contents of the lookahead aren’t matched. We negate it (the (?!) group) so that it
    doesn’t match stuff after our fraction – that way, we don’t match the group in what follows.

    The complement to a lookahead is a lookbehind (a (?<=) group) does the opposite – it matches stuff if it’s preceeded by this other stuff, and just like the lookahead, we can negate it (the (?<!) group) so that we can match things that don’t follow something.

    Together, they ensure that our fraction doesn’t have other parts of fractions before or after it. It places no other arbitrary requirements on the input data. It will match the fraction 2/3 in the string "te2/3xt", unlike most of the other examples provided.

    If your regex flavor uses //s to delimit regular expressions, you’ll have to escape the slashes in that, or use a different delimiter (Perl’s m{} would be a good choice here).


    Edit: Apparently, none of these regexes work because the regex engine is backtracking and matching fewer numbers in order to satisfy the requirements of the regex. When I’ve been working on one regex for this long, I sit back and decide that maybe one giant regex is not the answer, and I write a function that uses a regex and a few other tools to do it for me. You’ve said you’re using Ruby. This works for me:

    >> def get_fraction(s)
    >>   if s =~ /(\d+)\/(\d+)(\/\d+)?/
    >>     if $3 == nil
    >>       return $1, $2
    >>     end
    >>   end
    >>   return nil
    >> end
    => nil
    >> get_fraction("1/2")
    => ["1", "2"]
    >> get_fraction("1/2/3")
    => nil
    

    This function returns the two parts of the fraction, but returns nil if it’s a date (or if there’s no fraction). It fails for "1/2/3 and 4/5" but I don’t know if you want (or need) that to pass. In any case, I recommend that, in the future, when you ask on Stack Overflow, “How do I make a regex to match this?” you should step back first and see if you can do it using a regex and a little extra. Regular expressions are a great tool and can do a lot, but they don’t always need to be used alone.


    EDIT 2:

    I figured out how to solve the problem without resorting to non-regex code, and updated the regex. It should work as expected now, though I haven’t tested it. I also went ahead and escaped the /s since you’re going to have to do it anyway.

    EDIT 3:

    I just fixed the bug j_random_hacker pointed out in my lookahead and lookbehind. I continue to see the amount of effort being put into this regex as proof that a pure regex solution was not necessarily the optimal solution to this problem.

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