Question

I’m trying to commit git patches via a bash script. This is not a git question! Here is what I want to do, I have a list of files in a directory. I want read those files one by one extract a particular line out of it and then commit.
Here is what I got so far;

patches=/{location}/*.patch
for patch in $patches
do
  echo "Processing $patch file..."
  git apply $patch
  git add --all
  git commit -m | egrep -o "(^Subject: \[PATCH [0-9]\/[0-9]\].)(.*)$" $f
  echo "Committed $patch file..."
done

Couldn’t get the egrep regex working to pass on the proper commit message.
Here is an example line from a patch file;

.....
Subject: [PATCH 1/3] XSR-2756 Including ldap credentials in property file.  
......

I just want to capture “XSR-2756 Including ldap credentials in property file.” and use as a commit description to git.

Answer 1

Assuming you have GNU grep, use a Perl look-behind:

git commit -m "$(grep -Po '(?<=Subject: \[PATCH \d/\d\].).*') $patch"