Question

I’m trying to compare a regulare text to my input and if this specific condition is happening i want to print something, if not, just keep running.

This is the code:

int main()

{
    int c;
    c = getchar();

    while (c != EOF)

    {
        putchar(c);

        if (c == 'nir')
        {
            printf ("you typed nir");
        }

        c = getchar();
    }
}

Answer 1

The question is a little too confused for me to answer it all at once, so let’s begin at the beginning. To begin, 'nir' (if it compiles at all) is a very strange way to write a single integer, whereas I think that you meant "nir", a string of text. However, (c == "nir") does not compile, does it? [This presumably is why you have tried (c == 'nir') as a random shot, isn’t it, though it means nothing sensible in C.]

In the context in which you use it, the "nir" is an address. Now, you probably don’t know what this means yet — nor will you until you have gained several weeks’ more experience in C. What you can use today is the standard library’s strcmp() function, presented by string.h. I would recommend that you look that up and go from there.

And don’t type 'nir' again, incidentally! It means nothing sensible in C. The single quotes are for a single character like 'n', and stand for the character’s integral ASCII value.