Sign Up

Sign Up to our social questions and Answers Engine to ask questions, answer people’s questions, and connect with other people.

Have an account? Sign In

Have an account? Sign In Now

Sign In

Login to our social questions & Answers Engine to ask questions answer people’s questions & connect with other people.

Sign Up Here

Forgot Password?

Don't have account, Sign Up Here

Forgot Password

Lost your password? Please enter your email address. You will receive a link and will create a new password via email.

Have an account? Sign In Now

You must login to ask a question.

Forgot Password?

Need An Account, Sign Up Here

Please briefly explain why you feel this question should be reported.

Please briefly explain why you feel this answer should be reported.

Please briefly explain why you feel this user should be reported.

Sign InSign Up

The Archive Base

The Archive Base Logo The Archive Base Logo

The Archive Base Navigation

  • SEARCH
  • Home
  • About Us
  • Blog
  • Contact Us
Search
Ask A Question

Mobile menu

Close
Ask a Question
  • Home
  • Add group
  • Groups page
  • Feed
  • User Profile
  • Communities
  • Questions
    • New Questions
    • Trending Questions
    • Must read Questions
    • Hot Questions
  • Polls
  • Tags
  • Badges
  • Buy Points
  • Users
  • Help
  • Buy Theme
  • SEARCH
Home/ Questions/Q 771733
In Process

The Archive Base Latest Questions

Editorial Team
  • 0
Editorial Team
Asked: May 14, 20262026-05-14T18:41:59+00:00 2026-05-14T18:41:59+00:00

I’m trying to construct a dictionary that contains a series of sets: {Field1:{Value1, Value2,

  • 0

I’m trying to construct a dictionary that contains a series of sets:

{Field1:{Value1, Value2, Value3}, Field2{Value4}}

The trouble is, I then wish to delete any fields from the dictionary that only have one value in the set. I have been writing code like this:

for field in FieldSet:
    if len(FieldSet[field]) == 1:
        del(FieldSet[field])

But receive the error “RuntimeError: dictionary changed size during execution”. (Not surprising, since that’s what I’m doing.) It’s not the be-all and end-all if I have to knock together some sort of workaround, but is it possible to do this?

  • 1 1 Answer
  • 0 Views
  • 0 Followers
  • 0
Share
  • Facebook
  • Report

Leave an answer
Cancel reply

You must login to add an answer.

Forgot Password?

Need An Account, Sign Up Here

1 Answer

  • Voted
  • Oldest
  • Recent
  • Random
  1. Editorial Team
    Editorial Team
    2026-05-14T18:41:59+00:00Added an answer on May 14, 2026 at 6:41 pm

    Iterate over the return value from .keys() instead. Since you get a list of keys back, it won’t be affected by changing the dictionary after you’ve called it.

    • 0
    • Reply
    • Share
      Share
      • Share on Facebook
      • Share on Twitter
      • Share on LinkedIn
      • Share on WhatsApp
      • Report

Sidebar

Related Questions

link Im having trouble converting the html entites into html characters, (&# 8217;) i
I'm parsing an RSS feed that has an ’ in it. SimpleXML turns this
I'm trying to convert HTML to plain text. I get many &\#8217; &\#8220; etc.
I'm trying to create an if statement in PHP that prevents a single post
I am trying to understand how to use SyndicationItem to display feed which is
Basically, what I'm trying to create is a page of div tags, each has
I am trying to find ID3V2 tags from MP3 file using jid3lib in Java.
That's pretty much it. I'm using Nokogiri to scrape a web page what has
I've got a string that has curly quotes in it. I'd like to replace
I have a small JavaScript validation script that validates inputs based on Regex. I

Explore

  • Home
  • Add group
  • Groups page
  • Communities
  • Questions
    • New Questions
    • Trending Questions
    • Must read Questions
    • Hot Questions
  • Polls
  • Tags
  • Badges
  • Users
  • Help
  • SEARCH

Footer

© 2021 The Archive Base. All Rights Reserved
With Love by The Archive Base

Insert/edit link

Enter the destination URL

Or link to existing content

    No search term specified. Showing recent items. Search or use up and down arrow keys to select an item.