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Home/ Questions/Q 522035
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Editorial Team
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Editorial Team
Asked: May 13, 20262026-05-13T08:18:46+00:00 2026-05-13T08:18:46+00:00

I’m trying to convert a 3D rotation described in term of euler angles into

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I’m trying to convert a 3D rotation described in term of euler angles into a matrix and then back, using .NET/C#. My conventions are:

  • left handed system (x right, y top, z forward)
  • order of rotations: heading around y, pitch around x, bank around z
  • rotations are positive using the left hand rule (thumb pointing to +infinity)

My trial is:

Euler to matrix (I’ve removed the x,y,z translation part for simplification)

Matrix3D matrix = new Matrix3D() {
    M11 =   cosH * cosB - sinH * sinP * sinB,
    M12 = - sinB * cosP,
    M13 =   sinH * cosB + cosH * sinP * sinB,
    M21 =   cosH * sinB + sinH * sinP * cosB,
    M22 =   cosB * cosP,
    M23 =   sinB * sinH - cosH * sinP * cosB,
    M31 = - sinH * cosP,
    M32 = - sinP,
    M33 =   cosH * cosP,
};

Matrix to Euler

const double RD_TO_DEG = 180 / Math.PI;            
double h, p, b; // angles in degrees

// extract pitch
double sinP = -matrix.M23;            
if (sinP >= 1) {
    p = 90; }       // pole
else if (sinP <= -1) {
    p = -90; } // pole
else {
    p = Math.Asin(sinP) * RD_TO_DEG; }             

// extract heading and bank
if (sinP < -0.9999 || sinP > 0.9999) { // account for small angle errors
    h = Math.Atan2(-matrix.M31, matrix.M11) * RD_TO_DEG;
    b = 0; }
else {
    h = Math.Atan2(matrix.M13, matrix.M33) * RD_TO_DEG;
    b = Math.Atan2(matrix.M21, matrix.M22) * RD_TO_DEG; }

It must be wrong. If I take 3 angles, convert them into a matrix and convert the matrix back into angles, the result if different than the intial values.

I have browsed several sites with different formulas, starting with euclideanspace.com, but I’m now completely lost, and can’t find the right computations. I’ appreciate a little help. Is there a mathematician onboard?

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-13T08:18:46+00:00Added an answer on May 13, 2026 at 8:18 am

    Firstly, should:

    sinP = -matrix.M32
    

    EDIT: Full solution follows

    My derivation:

    Rx(P)=| 1      0       0 |
          | 0  cos P  -sin P |
          | 0  sin P   cos P |
    
    Ry(H)=|  cos H  0  sin H |
          |      0  1      0 |
          | -sin H  0  cos H |
    
    Rz(B)=| cos B  -sin B  0 |
          | sin B   cos B  0 |
          |     0       0  1 |
    

    Multiplied with your ordering:

    R = Ry(H)*Rx(P)*Rz(B)
      = | cos H*cos B+sin H*sin P*sin B  cos B*sin H*sin P-sin B*cos H  cos P*sin H |
        |                   cos P*sin B                    cos B*cos P       -sin P |
        | sin B*cos H*sin P-sin H*cos B  sin H*sin B+cos B*cos H*sin P  cos P*cos H |
    

    Which gives reverse derivations:

    tan B = M12/M22

    sin P = -M32

    tan H = M31/M33

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