Question

I’m trying to convert text into xml format. And I’m using LXML Library. But I’m getting error message. Please help me. Thank you

import re
from lxml import etree
import urllib,urllib2
def get_movie_info(movie_id):
    URL = "http://www.raaga.com/a/rss.asp?%s"%(movie_id)
    f = urllib.urlopen(URL)
    movie_info = f.read()
    rss = "".join([ line.strip() for line in movie_info ])
    mi_tree = etree.fromstring(rss)
    #mi_title = self._parse_movie_title(mi_tree.xpath("/rss/channel/title/text()")[0])
    #mi_tracks = mi_tree.xpath("/rss/channel/item")
    return mi_tree

get_movie_info('A0000102')

Here is my traceback

    Traceback (most recent call last):
  File "py1.py", line 14, in <module>
    get_movie_info('A0000102')
  File "py1.py", line 9, in get_movie_info
    mi_tree = etree.fromstring(rss)
  File "lxml.etree.pyx", line 2743, in lxml.etree.fromstring (src/lxml\lxml.etre
e.c:52665)
  File "parser.pxi", line 1573, in lxml.etree._parseMemoryDocument (src/lxml\lxm
l.etree.c:79932)
  File "parser.pxi", line 1452, in lxml.etree._parseDoc (src/lxml\lxml.etree.c:7
8774)
  File "parser.pxi", line 960, in lxml.etree._BaseParser._parseDoc (src/lxml\lxm
l.etree.c:75389)
  File "parser.pxi", line 564, in lxml.etree._ParserContext._handleParseResultDo
c (src/lxml\lxml.etree.c:71739)
  File "parser.pxi", line 645, in lxml.etree._handleParseResult (src/lxml\lxml.e
tree.c:72614)
  File "parser.pxi", line 585, in lxml.etree._raiseParseError (src/lxml\lxml.etr
ee.c:71955)
lxml.etree.XMLSyntaxError: xmlParsePITarget: invalid name prefix 'xml', line 1,
column 13

Answer 1

It works fine for me without this string:

rss = "".join([ line.strip() for line in movie_info ])

Something like this:

mi_tree = etree.fromstring(movie_info)