Question

I’m trying to convert this date format (in PHP): “dd/mm/yyyy”, for example 18/08/2011, into “j M Y” which should output something like this, “18 August 2011”.

If anyone could help, it would be much appreciated,
Thanks.

Answer 1

<?php 
   $str = "18/08/2011";
    preg_match("|(.*?)/(.*?)/(.*?)|", $str, $match);
    $str = $match[2]."/".$match[1]."/".$match[2];
    echo $your_format = date("j M Y", strtotime($str)); //strtotime() expects mm/dd/yyyy
    //returns 18 Aug 2008
?> 

http://sandbox.phpcode.eu/g/29439.php