Question

I’m trying to copy PIN (there is data inside PIN) to temp. (Assuming PIN is always smaller than temp)

const char * PIN;
.... 
char [10] temp  ="";
int i = 0; 
while (*(PIN+i)) {
    temp[i] = (PIN+i)*;
    i++;
}

Also would it be okay if I treated temp like a pointer as such?

long int res = strtol (&temp, NULL, 10);

Answer 1

A few things,

temp =”\0″
Will actually put two \0 in the string, the one you wrote, and one implied by the quotation.

PIN+i needs to be dereferenced (with a *) or it will go on and on unless you can guarantee a null pointer at the end of the address space.

while (*(PIN+i))

Then to copy the characters rather than the pointers the assignment statement should also be dereferenced.

temp[i]=*(PIN+i);
i++; // Because the pointer needs to be incremented

Also why wouldn’t you just use strcpy? or strncpy?