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Home/ Questions/Q 3457956
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Editorial Team
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Editorial Team
Asked: May 18, 20262026-05-18T09:55:25+00:00 2026-05-18T09:55:25+00:00

I’m trying to create a C array of objective C NSStrings using malloc. I’m

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I’m trying to create a C array of objective C NSStrings using malloc. I’m not doing it right, but I don’t think I’m far off. Maybe someone can point me in the right direction.
Let’s say we want 5 strings in our array for the sake of argument.

Interface:

@interface someObject : NSObject {
    NSString **ourArray;
}
@property () NSString **ourArray;
@end

Implementation:

@implementation someObject
@synthesize ourArray;

-(id)init {
    if((self = [super init])) {
        self->ourArray = malloc(5 * sizeof(NSString *));
    }
    return self;
}

-(NSString *)getStringAtPos3 {
    if(self.ourArray[3] == nil) {
        self.ourArray[3] = @"a string";
    }
    return self.ourArray[3];
}
@end

When I set a breakpoint in getStringAtPos3 it doesn’t see the array element as nil so it never goes into the if statement.

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  1. Editorial Team
    Editorial Team
    2026-05-18T09:55:26+00:00Added an answer on May 18, 2026 at 9:55 am

    I figured out the problem – I should have been using calloc, not malloc. While malloc simply allocates the memory, calloc

    contiguously allocates enough space for count objects that are size bytes of memory each and returns a pointer to the allocated memory. The allocated memory is filled with bytes of value zero.

    This means you get an array of nil objects essentially as in objective c 0x0 is the nil object.

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