Question

I’m trying to create a customer. I’m trying to add each user input inside an arrayList and make it output towards the end. But, my output gives me some memory location.Can someone throw some light into this?

public static void main(String[] args) {

    Scanner input = new Scanner(System.in);
    System.out.println("Enter First Name: ");
    String firstName = input.nextLine();
    System.out.println("Enter Last Name: ");
    String lastName = input.nextLine();
    System.out.println("Enter Home Address: ");
    String homeAddress = input.nextLine();

    Customer cus = new Customer(firstName, lastName, homeAddress);

    System.out.println("\nWelcome: ");
    System.out.print(cus.getFirstName() + cus.getLastName());
    System.out.println("\n Your Shipping Address: ");
    System.out.print(cus.getHomeShippingAddress());

    List<Customer> customer = new ArrayList<Customer>();

    customer.add(cus);

    // Output the list contents
    printList(customer);

}

public static void printList(List<Customer> list) {

    System.out.println("Customers: ");

    for (Customer customer : list) {
        System.out.printf("%s", customer);
    }
    System.out.println();
}

}

Answer 1

You’re trying to print an object, so it goes to its toString() method. You probably want to implement your own toString() method by overriding the one inherited from Object.

Something like:

@Override 
public String toString() {
    StringBuilder result = new StringBuilder();
    //build your string here. 
    //Perhaps by appending the customer's first and last name?
    return result.toString();
}

What you’re currently seeing, inherited from Object, is this:

getClass().getName() + ‘@’ + Integer.toHexString(hashCode())