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Home/ Questions/Q 8075213
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Editorial Team
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Editorial Team
Asked: June 5, 20262026-06-05T14:54:55+00:00 2026-06-05T14:54:55+00:00

I’m trying to create a data structure in C to represent graph. I found

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I’m trying to create a data structure in C to represent graph. I found this very useful link:

http://pine.cs.yale.edu/pinewiki/C/Graphs

It seems to me a quite good starting point. But I have some problem understanding the data structure.

struct graph {
    int n;              /* number of vertices */
    int m;              /* number of edges */
    struct successors {
        int d;          /* number of successors */
        int len;        /* number of slots in array */
        char is_sorted; /* true if list is already sorted */
        int list[1];    /* actual list of successors */
    } *alist[1];
};

I can’t understand why the struct successor is declared as it is and not in this way:

struct graph {
    int n;              /* number of vertices */
    int m;              /* number of edges */
    struct successors {
        int d;          /* number of successors */
        int len;        /* number of slots in array */
        char is_sorted; /* true if list is already sorted */
        int *list;    /* actual list of successors */
    } *alist;
};

As I can see in the sequent function to create the graph:

Graph
graph_create(int n)
{
    Graph g;
    int i;

    g = malloc(sizeof(struct graph) + sizeof(struct successors *) * (n-1));
    assert(g);

    g->n = n;
    g->m = 0;

    for(i = 0; i < n; i++) {
        g->alist[i] = malloc(sizeof(struct successors));
        assert(g->alist[i]);

        g->alist[i]->d = 0;
        g->alist[i]->len = 1;
        g->alist[i]->is_sorted= 1;
    }

    return g;
}

It allocates more spaces for alist and I can’t understand why declare it as alist[1].
Can you please explain me how this works?

I hope the question is clear, because I’m quite confused myself.

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-06-05T14:54:57+00:00Added an answer on June 5, 2026 at 2:54 pm
     struct successors {
         /*
         */
         int list[1];    /* actual list of successors */
     } *alist[1];
    

    Uses double indirection (each pointer op */& and the subscript operator [] is a level of indirection and requires an additional memory access) on the alist member to enable each index to be malloc‘d.

    struct successors {
         /*
         */
        int *list;    /* actual list of successors */
    } *alist;
    

    Does not.

    Also, from your link:

     /* basic directed graph type */
     typedef struct graph *Graph;
    

    That link has quite a lot of code.

    I don’t fully understand how ->list is used but your approach only reserves space for int * while the original reserves both the pointer and the target int.

    The allocation of

    g = malloc(sizeof(struct graph) + sizeof(struct successors *) * (n-1));
    

    only allocs successors * so each successors object can (in theory) be crudely extended to point to more int‘s.

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