Sign Up

Sign Up to our social questions and Answers Engine to ask questions, answer people’s questions, and connect with other people.

Have an account? Sign In

Have an account? Sign In Now

Sign In

Login to our social questions & Answers Engine to ask questions answer people’s questions & connect with other people.

Sign Up Here

Forgot Password?

Don't have account, Sign Up Here

Forgot Password

Lost your password? Please enter your email address. You will receive a link and will create a new password via email.

Have an account? Sign In Now

You must login to ask a question.

Forgot Password?

Need An Account, Sign Up Here

Please briefly explain why you feel this question should be reported.

Please briefly explain why you feel this answer should be reported.

Please briefly explain why you feel this user should be reported.

Sign InSign Up

The Archive Base

The Archive Base Logo The Archive Base Logo

The Archive Base Navigation

  • Home
  • SEARCH
  • About Us
  • Blog
  • Contact Us
Search
Ask A Question

Mobile menu

Close
Ask a Question
  • Home
  • Add group
  • Groups page
  • Feed
  • User Profile
  • Communities
  • Questions
    • New Questions
    • Trending Questions
    • Must read Questions
    • Hot Questions
  • Polls
  • Tags
  • Badges
  • Buy Points
  • Users
  • Help
  • Buy Theme
  • SEARCH
Home/ Questions/Q 615837
In Process

The Archive Base Latest Questions

Editorial Team
  • 0
Editorial Team
Asked: May 13, 20262026-05-13T18:15:46+00:00 2026-05-13T18:15:46+00:00

I’m trying to create a drawable in xml, a rectangle with one gradient on

  • 0

I’m trying to create a drawable in xml, a rectangle with one gradient on the top half, and another on the bottom half. This is NOT the way to do it, apparently:

<?xml version="1.0" encoding="utf-8"?>
<layer-list xmlns:android="http://schemas.android.com/apk/res/android">
    <item>
        <shape android:shape="rectangle">
                <gradient
                        android:startColor="#5a5a5a88"
                        android:endColor="#14141488"
                        android:angle="270" android:centerX="0.25"/>

        </shape>
    </item>
    <item>
        <shape android:shape="rectangle" android:top="80px">
                <gradient
                        android:startColor="#5aff5a88"
                        android:endColor="#14ff1488"
                        android:angle="270" android:centerX="0.25"/>

        </shape>
    </item>
</layer-list>

How can I do this, preferably in a way that makes it stretchable to any height?

  • 1 1 Answer
  • 0 Views
  • 0 Followers
  • 0
Share
  • Facebook
  • Report

Leave an answer
Cancel reply

You must login to add an answer.

Forgot Password?

Need An Account, Sign Up Here

1 Answer

  • Voted
  • Oldest
  • Recent
  • Random
  1. Editorial Team
    Editorial Team
    2026-05-13T18:15:46+00:00Added an answer on May 13, 2026 at 6:15 pm

    If your goal is to have a gradient with a central color (starts at color A, transitions to B in the middle, then transitions to C at the end), add android:centerColor and android:centerY attributes to one of your <shape> elements and nuke the other. You can do the three-color gradient all in a single shape.

    • 0
    • Reply
    • Share
      Share
      • Share on Facebook
      • Share on Twitter
      • Share on LinkedIn
      • Share on WhatsApp
      • Report

Sidebar

Ask A Question

Stats

  • Questions 487k
  • Answers 487k
  • Best Answers 0
  • User 1
  • Popular
  • Answers
  • Editorial Team

    How to approach applying for a job at a company ...

    • 7 Answers
  • Editorial Team

    How to handle personal stress caused by utterly incompetent and ...

    • 5 Answers
  • Editorial Team

    What is a programmer’s life like?

    • 5 Answers
  • Editorial Team
    Editorial Team added an answer Sure. You do need not a separate unit and can… May 16, 2026 at 8:15 am
  • Editorial Team
    Editorial Team added an answer please note that the "+"-sign is a css selector, this… May 16, 2026 at 8:15 am
  • Editorial Team
    Editorial Team added an answer Actually this curPageURL() function has nothing to do here if… May 16, 2026 at 8:15 am

Trending Tags

analytics british company computer developers django employee employer english facebook french google interview javascript language life php programmer programs salary

Related Questions

No related questions found

Top Members

Explore

  • Home
  • Add group
  • Groups page
  • Communities
  • Questions
    • New Questions
    • Trending Questions
    • Must read Questions
    • Hot Questions
  • Polls
  • Tags
  • Badges
  • Users
  • Help
  • SEARCH

Footer

© 2021 The Archive Base. All Rights Reserved
With Love by The Archive Base

Insert/edit link

Enter the destination URL

Or link to existing content

    No search term specified. Showing recent items. Search or use up and down arrow keys to select an item.